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-15x^2+600x+60=0
a = -15; b = 600; c = +60;
Δ = b2-4ac
Δ = 6002-4·(-15)·60
Δ = 363600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{363600}=\sqrt{3600*101}=\sqrt{3600}*\sqrt{101}=60\sqrt{101}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-60\sqrt{101}}{2*-15}=\frac{-600-60\sqrt{101}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+60\sqrt{101}}{2*-15}=\frac{-600+60\sqrt{101}}{-30} $
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